Saturday, September 6, 2014
All objects in a schema
SELECT b.name as 'schema_name', a.name, a.object_id, a.schema_id, a.parent_object_id, a.type, a.type_desc, a.create_date, a.modify_date
FROM sys.objects a INNER JOIN sys.schemas b ON a.schema_id = b.schema_id
WHERE object_id IN (select object_ID from sys.columns where name like 'snapshot%')
ORDER BY a.[type], b.name, a.name
--1760985600
SELECT b.name as 'schema_name', a.name, a.object_id, a.schema_id, a.parent_object_id, a.type, a.type_desc, a.create_date, a.modify_date
FROM sys.objects a INNER JOIN sys.schemas b ON a.schema_id = b.schema_id
WHERE object_id IN (select object_ID from sys.columns where name like 'snapshot%')
and b.name = 'snapshot'
and a.name = 'T2_Flatfile_snapshot_level'
ORDER BY a.[type], b.name, a.name
--823934257
SELECT b.name as 'schema_name', a.name, a.object_id, a.schema_id, a.parent_object_id, a.type, a.type_desc, a.create_date, a.modify_date
FROM sys.objects a INNER JOIN sys.schemas b ON a.schema_id = b.schema_id
WHERE object_id IN (select object_ID from sys.columns where name like 'snapshot%')
and b.name = 'dbo'
and a.name = 'Flatfile_snapshot'
ORDER BY a.[type], b.name, a.name
SELECT name, column_id FROM sys.columns where object_ID = 109503719
order by 2
union all
SELECT object_id, name, column_id FROM sys.columns where object_ID = 823934257
order by 2
Labels:
SQL Server,
T-SQL
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